Heat Transfer Questions & Answers | |
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I don't understand your question. As written in the problem statement there is no heat transfer to the journal.
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If you unroll the bearing into $xy$ coordinates, you have to give the same area to the bearing and the journal: otherwise this wouldn't be consistent. If you don't unroll the bearing and solve it in cylindrical coordinates, then you should use two different areas for the bearing and the journal.
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I'm not sure what is confusing you. As you mention, when V.D. is important, $q^"=h(T_{\rm w}-T_{\rm aw})$.
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You can use other correlations too unless they specifically say they are not applicable to liquids.
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You're on the right track, but this is not correct still. Work on it more — the diameter of the tubes should be somewhere in your areas.. Also, use the PREVIEW command and make sure your math show up clearly: your expressions are too close to each other and hard to read. Separate them on different lines.
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$\pi$ |